Physics, asked by shishukumar, 11 months ago

if Q lies between p and R and p r is equal to 13 QR is equal to 7 then PQ square + QR is equal to​

Answers

Answered by lovingheart
3

Answer:

The  final value is 42

Explanation:

Step 1:

Refer below attached diagram

Using line diagram representing the value of PQ and QR and PR

Step 2:

Given values:

The value of PR=13    

The value of  QR=7

The value of PQ=?

[To find the value of PQ subtract the value of PR to subtract the value of QR]

PQ=PR-QR  

13-7=6

PQ=6

The value of PQ is 6

STEP 3:

To find the value of \mathrm{PQ}^{2}+\mathrm{QR}

=6 x 6+7  

=36+7

=42

Attachments:
Similar questions