find k:k=xy-(3xy-xy(2x+3y-x))
Answers
Answered by
2
xy - (3xy - xy • (x + 3y))
x2y + 3xy2 - 2xy = xy • (x + 3y - 2)
xy • (x + 3y - 2)
Answered by
0
Answer:
(x+y)(2x−5y+3xy)
=x(2x−5y+3xy)+y(2x−5y+3xy)
=2x
2
−5xy+3x
2
y+2xy−5y
2
+3xy
2
=2x
2
+(−5xy+2xy)+3x
2
y+3xy
2
−5y
2
(Combiningliketerms)
=2x
2
+xy(−5+2)+3x
2
y+3xy
2
−5y
2
=2x
2
−3xy+3x
2
y+3xy
2
−5y
2
Hence, (x+y)(2x−5y+3xy)=2x
2
−3xy+3x
2
y+3xy
2
−5y
2
.
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