Math, asked by nirvaan32, 6 hours ago

find k:k=xy-(3xy-xy(2x+3y-x))

Answers

Answered by Ananyanair2010
2

 xy -  (3xy -  xy • (x + 3y))

  x2y + 3xy2 - 2xy  =   xy • (x + 3y - 2)  

 xy • (x + 3y - 2)

Answered by Anonymous
0

Answer:

(x+y)(2x−5y+3xy)

=x(2x−5y+3xy)+y(2x−5y+3xy)

=2x

2

−5xy+3x

2

y+2xy−5y

2

+3xy

2

=2x

2

+(−5xy+2xy)+3x

2

y+3xy

2

−5y

2

(Combiningliketerms)

=2x

2

+xy(−5+2)+3x

2

y+3xy

2

−5y

2

=2x

2

−3xy+3x

2

y+3xy

2

−5y

2

Hence, (x+y)(2x−5y+3xy)=2x

2

−3xy+3x

2

y+3xy

2

−5y

2

.

Similar questions