Question

find k so that 3k-2
, 2k^2-5k+8 & 4k+3 are in A.P

Answer 1

Hi ,

Let a1 = 3k - 2 ,

a2 = 2k² - 5k + 8 ,

a3 = 4k + 3 are three terms in A.P

we know that ,

a2 - a1 = a3 - a2

2k² - 5k + 8 - ( 3k - 2 ) = 4k + 3 - ( 2k² - 5k + 8 )

2k² - 5k + 8 - 3k + 2 = 4k + 3 - 2k² + 5k - 8

4k² - 8k - 9k + 10 + 5 = 0

4k² - 17k + 15 = 0

4k² - 12k - 5k + 15 = 0

4k ( k - 3 ) - 5 ( k - 3 ) = 0

( k - 3 ) ( 4k - 5 ) = 0

k - 3 = 0 or 4k - 5 = 0

k = 3 or k = 5/4

I hope this helps you.

:)

Answer 2

hey mate here ia yur answer

if yhis answer helps u pleaee mark it as a brainliest...