Question

Find k so that k, K+2, K+6 are
of a G.P.
​

Answer 1

$since \: they \: are \: i n \: gp \\ \\ \frac{k + 2}{k} = \frac{k + 6}{k + 2} \\ \\ {(k + 2)}^{2} = k(k + 6) \\ \\ {k}^{2} + 4 + 4k = {k}^{2} + 6k \\ \\ 4 = 6k - 4k \\ \\ 2k = 4 \\ \\ k = 2$

Answer 2

Answer:

k =2

Step-by-step explanation:

Since they are in gp

k + 2 / k = k + 6 / k + 2

(k + 2)² = k(k + 6)

k² + 4 + 4k = k² + 6k

4 = 6k - 4k

2k = 4

k =2

Thank ❤️

hope it helps you.

silentlover45.❤️