Find k so that one root of the equation Kx square-14x+8=0 is 2
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ur answer is correct
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Answer:
Here,. a=k,. b=-14,. C=8
We know that,
D=b²-4ac=0
»(-14)²-4×k×8=0
»196-32k=0
»-32k=-196
»k=196/32
»k=49/8
»k=6.125
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