find k so that the equation has unique solution
2x+3y=7 & 2kx(k+m)y=2
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Given : 2x+3y=7 & 2kx + (k+2)y =2
To find : k so that pair of linear equation has unique solution
Solution:
A pair of linear Equations
a₁x + b₁y = c₁ &
a₂x + b₂y = c₂
has unique Solution if
a₁/a₂ ≠ b₁/ b₂
2x+3y=7
2kx + (k+2)y =2
=> 2/2k ≠ 3/(k + 2)
=> k + 2 ≠ 3k
=> 2k ≠ 2
=> k ≠ 1
k ∈ R - {1}
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