Question

Find k so that the point p (-4,6) lies on the line segment joining a (k,10) and b (3,-8). Also find the ratio in which p divides ab

Answer 1

Answer:

Here is your answer

Step-by-step explanation:

Slope using points p and b

Slope = (6- -8)/(-4-3) = 14/-7 = -2

Slope using point a and p

Slope = (6-0)/(-4-k) = -2

6 = 8+2k

2k = -2

k = -1

ab = √(6²+3² = 3√5

pb = √14²+7² = 7√5

∴ap:pb = 3√5 : 7√5 = 3 : 7

Answer 2

Answer:

Here is your answer

Step-by-step explanation:

Slope using points p and b

Slope using points p and bSlope = (6- -8)/(-4-3) = 14/-7 = -2

Slope using points p and bSlope = (6- -8)/(-4-3) = 14/-7 = -2Slope using point a and p

Slope using points p and bSlope = (6- -8)/(-4-3) = 14/-7 = -2Slope using point a and pSlope = (6-0)/(-4-k) = -2

Slope using points p and bSlope = (6- -8)/(-4-3) = 14/-7 = -2Slope using point a and pSlope = (6-0)/(-4-k) = -26 = 8+2k

Slope using points p and bSlope = (6- -8)/(-4-3) = 14/-7 = -2Slope using point a and pSlope = (6-0)/(-4-k) = -26 = 8+2k2k = -2

Slope using points p and bSlope = (6- -8)/(-4-3) = 14/-7 = -2Slope using point a and pSlope = (6-0)/(-4-k) = -26 = 8+2k2k = -2k = -1

Slope using points p and bSlope = (6- -8)/(-4-3) = 14/-7 = -2Slope using point a and pSlope = (6-0)/(-4-k) = -26 = 8+2k2k = -2k = -1ab = √(6²+3² = 3√5

Slope using points p and bSlope = (6- -8)/(-4-3) = 14/-7 = -2Slope using point a and pSlope = (6-0)/(-4-k) = -26 = 8+2k2k = -2k = -1ab = √(6²+3² = 3√5pb = √14²+7² = 7√5

Slope using points p and bSlope = (6- -8)/(-4-3) = 14/-7 = -2Slope using point a and pSlope = (6-0)/(-4-k) = -26 = 8+2k2k = -2k = -1ab = √(6²+3² = 3√5pb = √14²+7² = 7√5∴ap:pb = 3√5 : 7√5 = 3 : 7