Question

For what value of k will k+9,2k-1 and 2k+7 are consecutive terms of an AP.

Answer 1

Heya mate, Here is ur answer

For given terms to be consecutive, there common difference must be same.

For example,

The consecutive terms of AP

1,2,3....

Has common difference

2-1=3-2

1=1

So,

AP: k+9 , 2k+1 , 2k+7 ........

2k+1-(k+9) = 2k+7 - (2k+1)

2k+1-k-9 = 2k+7 -2k -1

k -8 = 6

k=6+8

k= 14

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Warm regards

@Laughterqueen

Be Brainly✌✌

Answer 2

Here we ll use the formula to find the value of k:

[b-a]=[c-b]

2k-1-{k+9}= 2k+7-{2k-1]

2k-1-k-9=2k+7-2k+1

k-10=8

k=18.

Hope it helps.....