find k such that the quadratic equation x2-2kx+7k-12=0 as equal roots
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a = 1 , b = -2k , c = 7k-12
d = b^2 - 4ac
= 4k^2 - 4 × 1 × 7k-12
= 4k^2 - 28k + 48 = 0
= k^2 - 7k + 12 = 0
= (k-4) (k-3) = 0
= k = 4 , k = 3
plzz mark as brainliest answer !!!
d = b^2 - 4ac
= 4k^2 - 4 × 1 × 7k-12
= 4k^2 - 28k + 48 = 0
= k^2 - 7k + 12 = 0
= (k-4) (k-3) = 0
= k = 4 , k = 3
plzz mark as brainliest answer !!!
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