Question

find 'k' value .... chemical eqm​

Answer 1

$\huge\underline\green{\sf Answer}$

★$\large{\boxed{\sf K ={\frac{K_{2}{K_{3}}^{3}}{K_{1}}}}}$

$\huge\underline\green{\sf Solution}$

Here ,

$\large{\sf 2NH_{3}+O_{2} ⇋2NO :K}$

We have to Find K = ?

In the Question given Reaction we can write as :-

To get the above Reaction :-

$\large{\sf NH_{3}⇋N_{2}+3H_{2} :{\frac{1}{K_{1}}}}$

$\large{\sf N_{2}+O_{2} ⇋2NO :K_{2}}$

$\large{\sf 3H_{2}+{\frac{3}{2}}O_{2}⇋3H_{2}O :{K}_{3}^{3}}$

______________________________________

$\large{\sf NH_{3}+{\frac{3}{2}}O_{2}+O_{2} ⇋2NO+3H_{2}O}$

Add the Oxygen atom $\large{\sf O_{2}}$

★$\large{\sf NH_{3}+{\frac{5}{2}}O_{2}⇋2NO+3H_{2}O }$

Hence , K will be :-

★$\large\red{\boxed{\sf K ={\frac{K_{2}{K_{3}}^{3}}{K_{1}}}}}$