Question

find k where ap is k,2k-1,2k+1

Answer 1

difference between a2-a1=a3-a2
a1=k
a2=2k-1
a3=2k+1
2k-1-k=2k+1-(2k-1)
k-1=2
k=3


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Answer 2

Let a1 = k
      a2 = 2k - 1
      a3 = 2k + 1
Now, 
Common difference (d)= a2 -a1 = 2k - 1 - k = k - 1.
also 
d = a3 - a2 = 2k + 1 - (2k - 1) = 2 
Now, equating the values of d,we get
 k -1 = 2
thus,
k =3.
hope it helps...