Question

Find kif the quadratic equation has equal roots : kox (x-2) +6=0.​

Answer 1

Kox(x-2)+6

Kox^2-2k+6=0

B^2-4ac = 0

-2k^2-4(k)(6) =

4k^2. - 24k. = 0

4k^2. = 24k

K^2. = 6k

K. =. 6k/k

K = _+ 6