Find largest number which divides 318and739 leaving remender3and 4respectively
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Answered by
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Step 1 : Subtract 3 and 4 from 318 and 739 respectively
318 - 3 = 315
739 - 4 = 735
Step 2 : Find the prime factors of obtained numbers
315 = 3 × 3 × 5 × 7
735 = 3 × 5 × 7 × 7
Step 3 : Find the common factors
Common factors = 3 × 5 × 7
= 105
The product of the common factors of any numbers is their HCF itself and also the least number in this question
∴ HCF = 105
∴ The largest number which divides 318 and 739 leaving remainder 3 and 4 respectively is
318 - 3 = 315
739 - 4 = 735
Step 2 : Find the prime factors of obtained numbers
315 = 3 × 3 × 5 × 7
735 = 3 × 5 × 7 × 7
Step 3 : Find the common factors
Common factors = 3 × 5 × 7
= 105
The product of the common factors of any numbers is their HCF itself and also the least number in this question
∴ HCF = 105
∴ The largest number which divides 318 and 739 leaving remainder 3 and 4 respectively is
rishirajsharma197:
hi
Answered by
0
Subtract the reminders from the numbers, respectively.
318 - 3 = 315
739 - 4 = 735
Now, find the HCF of the numbers
315 = 3 × 3 × 5 × 7
735 = 3 × 5 × 7 × 7
HCF (315,735) = 3 × 5 × 7
HCF (315,735) = 105
Therefore the largest number which divides 318 and 739 leaving the reminders 3 and 4, respectively, is 105.
318 - 3 = 315
739 - 4 = 735
Now, find the HCF of the numbers
315 = 3 × 3 × 5 × 7
735 = 3 × 5 × 7 × 7
HCF (315,735) = 3 × 5 × 7
HCF (315,735) = 105
Therefore the largest number which divides 318 and 739 leaving the reminders 3 and 4, respectively, is 105.
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