find largest positive integers will divide 398 , 436 , 542 leaving remainders 7 ,11 , 15 respectively
Answers
Answered by
6
i hope this answer will help you
Attachments:
Answered by
0
Given :-
398 , 436 and 542
To Find :-
The largest number
Solution :-
Let’s assume the integer is x
According to the condition given in the question
⇒ xy+7 = 398
⇒ xz+11 = 436
⇒ xk+15 = 542
⇒ xy =391
⇒ xz = 425
⇒ xk = 527
⇒ 17 × 23 = 391
⇒ 17 × 25 = 425
⇒ 17 × 31 = 527
So, the largest possible integer that will divide 398,436,542 & leaves reminder 7,11 and 15 respectively was 17.
Similar questions