Question

find lcm and hcf of
(a³-b³) (a+b²) ,(a⁴-b⁴) and 3a⁴+2a³b-5a²b²​

Answer 1

Answer:

Step-by-step explanation:

(a³-b³)(a+b²)= (a-b)(a²+ab+b²)

(a⁴-b⁴)= (a+b)(a-b)(a²+b²)

(3a⁴+2a³b-5a²b²)= a²(3a²+2ab-5b²)

                            = a²(3a²-3ab+5ab-5b²)

                            = a²{3a(a-b)+5b(a-b)}

                            = a²(a-b)(3a+5b)

as (a-b) is common in all the factors so HCF is (a-b)

and LCM is rest potions along with a-b, =  a²(a-b)(a+b)(3a+5b)(a²+b²)(a²+ab+b²)