find lcm and hcf of the following pairs of integers and verify that lcm×hcf = product of two numbers 26 and 91
Answers
Answered by
15
Hey friend ....!! here's your answer
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First of fall...we need to find the factor of 26 and 91
26 = 2 × 13
91 = 7 × 13
LCM = 2 × 7 × 13 = 182
HCF = 13
so that the LCM is 182 and HCF is 13
Verification :
182 × 13 / 26 = 91
182 ×13 / 91 = 26
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#Hope its help you dear#
☺
__________________________
First of fall...we need to find the factor of 26 and 91
26 = 2 × 13
91 = 7 × 13
LCM = 2 × 7 × 13 = 182
HCF = 13
so that the LCM is 182 and HCF is 13
Verification :
182 × 13 / 26 = 91
182 ×13 / 91 = 26
______________________________
#Hope its help you dear#
☺
manish444:
thank u frd
ur wlcm
Answered by
9
Prime factors of 26 and 91 are:-
26=2*13
91=7*13
Therefore,LCM=2*7*13=14*13=182
HCF=13
Verification:-
LHS RHS
HCF*LCM Product of numbers
182*13 26*91
=2366 = 2366
LHS=RHS
Hence verified.
Hope it helps...
26=2*13
91=7*13
Therefore,LCM=2*7*13=14*13=182
HCF=13
Verification:-
LHS RHS
HCF*LCM Product of numbers
182*13 26*91
=2366 = 2366
LHS=RHS
Hence verified.
Hope it helps...
can u give one more solution
can ask
510 and 92
Yes
Prime factors of 510 and 92 are:- 510:-2*3*5*17. 92:-2*2*23. Therefore, LCM=2*2*3*5*17*23=23460. HCF=2. Verification:- LHS. RHS. HCF*LCM. Product of numbers 2*23460. 510*92. 46920. 46920. LHS=RHS. Hence verified. Hope it helps!!!
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