Question

Find LCM ofx2-4andx4-16

Answer 1

${x }^{2} - 4 = (x - 2)(x + 2) \\ {x}^{4} - 16 = ( {x}^{2} - 4)( {x}^{2} + 4) \\ > > > > = (x + 2)(x - 2) \\ so \: lcm = (x + 2)(x - 2) = {x}^{2} - 4$