Question

find least and greatest value of
3 cos o + 4 sino + 5​

Answer 1

Answer:

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Solution:

3 cos x + 4 sin x + 5

The minimum value of a cos θ + b sin θ + c is c – √(a2 + b2)

Substituting a = 3, b = 4, c = 5,

c – √(a2 + b2) = 5 – √(9 + 16) = 5 – √25 = 5 – 5 = 0

Therefore, the minimum value of 3 cos x + 4 sin x + 5 is 0.