find length of hypotenuse of isosceles right angled triangle having area of 200cm2. (take root2=1.414)
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1/2 bh =area of triangle.
here the base and height of isosceles right triangle are equal. Base and height are two side of the triangle.
hence area of triangle is 1/2 s^2=200
s^2 = 400
sq root on both sides
s = 20
now by pythagoreas theorem
s^2+s^2=hypotenuse ^2
20^2+20^2=h^2
400+400=h^2
800=h^2
h=√800
h=20√2
h=20×1.414
h=28.28
Therefore the length of hypotenuse is 28.28 cm
_____ _____
_____ Hope it helps you _____
here the base and height of isosceles right triangle are equal. Base and height are two side of the triangle.
hence area of triangle is 1/2 s^2=200
s^2 = 400
sq root on both sides
s = 20
now by pythagoreas theorem
s^2+s^2=hypotenuse ^2
20^2+20^2=h^2
400+400=h^2
800=h^2
h=√800
h=20√2
h=20×1.414
h=28.28
Therefore the length of hypotenuse is 28.28 cm
_____ _____
_____ Hope it helps you _____
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