find limit x tends to 0 sin77x÷sin11x
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Answer:
We have
lim
x→0
x
sinx
=1 when x is in radians
also, x
∘
=
180
π
x radians
∴lim
x→0
x
sinx
∘
=lim
x→0
x
sin
180
πx
=lim
x→0
(
180
πx
)×(
π
180
)
sin(
180
πx
)
⇒lim
x→0
x
sinx
∘
=
180
π
lim
x→0
(
180
πx
)
sin(
180
πx
)
=
180
π
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