Math, asked by alenmathews6565, 2 months ago

find limite x→3. x^3-9x÷x³-8x²+15x

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Answered by bhumi4653

1

$+ 1 \\ \sqrt[ {x}^{3} - 9x]{ {x}^{3} { - 8x}^{2} + 15x } \\ \: \: \: \: \: \: \: \: {x}^{3} \: \: \: \: \: \: \: \: \: \: \: \: - 9x \\ - \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: + \\ \: \: \: \: \: \: \: \: \: - - - - - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - {8x}^{2} + 24x$

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