Question

Find lowest number which divides 615 and 963 leaving remainder 6?

Answer 1

Answer:

subtract 6 from given numbers and find their hcf

Step-by-step explanation:

615-6=609

963-6=957

now hcf of 609 and 957

609=3*7*29

957=3*11*29

hcf of 609 and 957is 3*29=87

:the lowest number which divides 615and 963 leaving remainder 6is 87.

Answer 2

Step-by-step explanation:

To find the largest number,

which divides 615 and 963 leaving remainder 6 in each case.

We have to find HCF.

615 = 3*3*29

963 = 3*11*29

HCF = 3*29 = 87

87 is the largest number which divides 615 and 963 leaving remainder 6 in each case.