find <BCD
in the given figure -
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Make a triangle that consists points B and C
Extend line AB : This makes a good triangle.
Now, AB extended is parallel to DE too.
Two angles inside the triangle will be 75° and 35°.
Sum of angles is always 180°
The remaining angle is ∠BCD.
180°-75°-35°=70°
Angle BCD is 70°
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