find the value of k if kx(x+2)+4=0 has distinct real roots
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Answer:
kx(x+2)+4=0
Step 1: Add -4 to both sides.
kx2+2kx+4+−4=0+−4
kx2+2kx=−4
Step 2: Factor out variable k.
k(x2+2x)=−4
Step 3: Divide both sides by x^2+2x.
k(x2+2x)
x2+2x
=
−4
x2+2x
k=
−4
x2+2x
Answer:
k=
−4
x2+2x
Step-by-step explanation:
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