Question

Find m if (m-12)x^2+2(m-12)x+2=0 has real and unequal roots <br />

Answer 1

Answer:

m=12 or 14

Step-by-step explanation:

(m-12)x^2+2(m-12)x+2=0

a=m-12

b=2(m-12)

c=2

since the equation has real and distinct roots,b^2-4ac>0

[2(m-12)]^2-4*(m-12)*2>0

(2m-24)^2-(4m-48)2>0

4m^2-96m+576-8m+96>0

4m^2-104m+672>0

m^2-26m+168>0

m^2-14m-12m+168>0

m(m-14)-12(m-14)>0

(m-12)(m-14)>0

m=12 or 14