Question

find m if (m-12)x2+2(m-12)x+2=0 has real and equal roots

Answer 1

Hey,
Thanks for asking this question.

Given quadratic equation is,

(m-12)x^2 + 2(m-12)x + 2 = 0

Comparing this equation to the equation
ax^2 + bx + c = 0,

a = m-12
b = 2(m-12)
c = 2

●We know that a quadratic equation has a real and equal roots if and only if,
b^2 - 4ac = 0

=> {2(m-12)}^2 - 4(m-12)(2) = 0

=> 4 (m-12)^2 - 8(m-12) = 0

=> (m-12)^2 - 2(m-12) = 0

=> (m-12)(m-12-2) = 0

=> m = 12 or m= 14

●So value of is either 12 or 14 for the required situation.


●●● Hope My Answer Helped.

Answer 2

Answer:

Step-by-step explanation: