find m if (m-12)x2+2(m-12)x+2=0 has real and equal roots
Answers
Answered by
269
Hey,
Thanks for asking this question.
Given quadratic equation is,
(m-12)x^2 + 2(m-12)x + 2 = 0
Comparing this equation to the equation
ax^2 + bx + c = 0,
a = m-12
b = 2(m-12)
c = 2
●We know that a quadratic equation has a real and equal roots if and only if,
b^2 - 4ac = 0
=> {2(m-12)}^2 - 4(m-12)(2) = 0
=> 4 (m-12)^2 - 8(m-12) = 0
=> (m-12)^2 - 2(m-12) = 0
=> (m-12)(m-12-2) = 0
=> m = 12 or m= 14
●So value of is either 12 or 14 for the required situation.
●●● Hope My Answer Helped.
Thanks for asking this question.
Given quadratic equation is,
(m-12)x^2 + 2(m-12)x + 2 = 0
Comparing this equation to the equation
ax^2 + bx + c = 0,
a = m-12
b = 2(m-12)
c = 2
●We know that a quadratic equation has a real and equal roots if and only if,
b^2 - 4ac = 0
=> {2(m-12)}^2 - 4(m-12)(2) = 0
=> 4 (m-12)^2 - 8(m-12) = 0
=> (m-12)^2 - 2(m-12) = 0
=> (m-12)(m-12-2) = 0
=> m = 12 or m= 14
●So value of is either 12 or 14 for the required situation.
●●● Hope My Answer Helped.
amanbhati96737p9zk0u:
thanx for help
Answered by
141
Answer:
Step-by-step explanation:
Attachments:
Similar questions