find m if x+2 is divisible by x³-2mx²+16
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Answer:Given that, the polynomial x³-2mx²+16 is divisible by x+2
So, x+2 must be the factor of given polynomial
x+2=0
x=-2
So, -2 is the zero of given polynomial
x³-2mx²+16 = 0
Replacing x by -2
(-2)³-2m(-2)²+16 = 0
-8-8m+16 = 0
Taking -8 as common and passed to RHS
-8(1+m-2) = 0
1+m-2 = 0
m-1 = 0
m=1
therefore, the value of m in the given polynomial is 1
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