Question

Find m so that (–2)m + 1 × (–2)3

= (–2)9​

Answer 1

$(-2)^{m+1} \times (-2)^{3} = (-2)^{9}$

$\implies (-2)^{(m+1+3)} = (-2)^{9}$

$\boxed {\pink { a^{m} \times a^{n} = a^{m+n} }}$

$\implies (-2)^{m+4} = (-2)^{9}$

$\implies m + 4 = 9$

$\boxed {\pink { If \: a^{m} = a^{n} \:then \: m = n }}$

$\implies m = 9 - 4$

$\implies m = 5$

Therefore.,

$\red { Value \:of \: m } \green { = 5 }$

•••♪