Find "m"so that quadratic equation mx(x-7)+49=0, has 2equal roots.
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The given quadratic equation is mx (x-7)+49=0
mx2-7mx+49=0
a = m, b = -7m, c = 49
It is given that the roots of this equation are equal.
D = b2 - 4ac=0
(-7m)2 - 4(m)(49)=0
49m2 - 4(m)(49)=0
49m(m-4)=0
49m=0 or m - 4 = 0
m = 0 or m=4
For m = 0 equation will not be quadratic hence m = 4
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