Math, asked by guddimishram, 1 year ago

Find 'm'
${x}^{2} - 4x + 3m + 1 \:\: > 0 \: for \: all \: x > 0$

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Answered by bcute710

0

Step-by-step explanation:

Find 'm'

{x}^{2} - 4x + 3m + 1 \:\: > 0 \: for \: all \: x > 0x

2

−4x+3m+1>0forallx>0

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