Question

find magnetic flux of rectangular coil of size 6cm×8 cm placed at right angle of magnetic field of 0.5wb/m^2​

Answer 1

Answer:

Given that,

Number of turns N=60

Length l=20cm

Width b=10cm

Magnetic field B=0.5T

Rotation per min f=1800

We know that,

ϕ=(ABcosθ)N

ϕ=NABcosωt

dt

−dϕ

=ε

ε=−

dt

d(NABcosωt)

ε=−ABω(−sinωt)N

ε=NABωsinωt

ω=2πf

ε=2πfNABsinωt

ε

max

=2πfNAB

ε

max

=2×3.14×60×(20×10×10

−4

)×0.5×30

ε

max

=113.04volt

Hence, the maximum induced emf is 113.04volt