Question

Find maximum frequency and minimum wavelength of X-ray radiation, if the potential difference between
cathode and anode was (a) Ua1 = 5 kV and Ua2 = 11 kV.

Answer 1

ANSWER

If electrons are accelerated to a velocity v by a potential difference V and then allowed to collide with a metal target, the maximum frequency of the X-rays emitted is given by the equation:

mv

2

=eV=hν

or, λ

min

=

10

3

1240

∗10

−9

=124nm=12.4A