Math, asked by theanhsmiley2005, 2 months ago

Find maximum value of B=x^{3} (2-x^{5} )

Answers

Answered by JuanitaJ
1

Answer:

Points where derivative of the function is equal to zero are either maxima or minima since it is a continuous function.

putting derivative = 0 , we get

(4×−1×{7−x}

3

×{2+x}

5

)+(5×{7−x}

4

{2+x}

4

)=0.

or , 5{7−x}=4{2+x} since x∈(−2,7) so {x+2}

=0 & {7−x}

=0.

Therefore 9x=27 or , x=3.

Hence the maximum value will be (7−3)

4

(2+3)

5

or 8×10

5

.

Answered by barani79530
0

Step-by-step explanation:

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