Find maximum value of B=
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Points where derivative of the function is equal to zero are either maxima or minima since it is a continuous function.
putting derivative = 0 , we get
(4×−1×{7−x}
3
×{2+x}
5
)+(5×{7−x}
4
{2+x}
4
)=0.
or , 5{7−x}=4{2+x} since x∈(−2,7) so {x+2}
=0 & {7−x}
=0.
Therefore 9x=27 or , x=3.
Hence the maximum value will be (7−3)
4
(2+3)
5
or 8×10
5
.
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