Question

find maximum value of q in equation? 5p9+3r7+2q8= 1114
( explain)

Answer 1

hope it will satisfy u :)

Answer 2

The answer is 9.

(500+p0+9)+(300+R0+7)+(200+q0+8)=1114

.

(1000+24)+(p+q+r)10=1114

(1024)+(p+q+r)10 = 1114

1024+(p+q+r)=111.4

The max. Value of q is 9.because to keep q as maximum p and r should be 0.