Find mean of first 9 multiple of 3
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Answer:
12
Step-by-step explanation:
the first nine multiples of three are:3,6,9,12,15,18,21,24,27
so the mean of all these terms is:
(3+6+9+12+15+18+21+24+27)/9
now for easier calculations we can observe that the numerator is in Arithmetic progression with first term as 3 and common difference 3
sum of n term in an arithmetic progression is:
n(2a+(n-1)d)/2 so here number of terms(n)=9;a=3;d=3
9(6+18)/2=12*9=108 is our numerator
so the mean is simply 108/9 which is equal to 12
so the mean we require is 12
I REALLY HOPE THIS HELPS YOU
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