If a<_0, the roots of
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Case 1 : x≥ a so |x - a| = x - a x2 - 2a|x - a| - 3a2 = 0 x2 - 2ax + 2a2 - 3a2 = 0 x2 - 2ax = a2 x2 - 2ax + a2 = 2a2 Taking square root, x - a = ± a√(2)
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