find measure of all the four angle of a quadrilateral if two of them are twice of the third and fourth is 20degree more than the sum of two equal angle
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Step-by-step explanation:
Let x, y,z and w are four angles of quadrilateral.
According to question
x=2z,y=2z
w=(x+y)+20=2z+2z+20=4z+20
x+y+z+w=360^{\circ}
By the property of sum of angles of quadrilateral.
Substitute the values
2z+2z+z+4z+20=360
9z=360-20=340
z=\frac{340}{9}=37.8^{\circ}
z=37.8^{\circ}
x=y=2\times 37.8=75.6^{\circ}
w=4(37.8)+20=171.2^{\circ}
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