Find measure of the angles A and B, if cos(A-B) =√3/2 and sin (A+B)=√3/2
Answers
Answered by
5
Cos (A-B) = √3/2
sin ( A+B) = √3/2
(A-B) =30 degree (1)
(A+B)= 60 degree(2)
add the eq (1) and (2)
A=90/2 =45 degree
put the value of A in Eq (1)
45-B=30
B=15
sin ( A+B) = √3/2
(A-B) =30 degree (1)
(A+B)= 60 degree(2)
add the eq (1) and (2)
A=90/2 =45 degree
put the value of A in Eq (1)
45-B=30
B=15
Similar questions