Find Median and mode of the following
distribution table
Class Iterval
- 0-10 10-20
20-30
30- 40
40-50 50-60
Frequency
3
16
26
31 16 8 plz explain
Answers
median = l + ( 3N/4 - CF)/ f * C mode = l + ( f1 - f0 / 2f1 - f0 - f2) * c
MEDIAN
classes Frequency CF
0-10 3 3
10-20 16 19
20-30 26 45
30-40 31 76
40-50 16 92
50-60 8 100
to find cumulative frequency first keep the first value acid is that is 3 next add 16 + 3 then you get 19 + 26 45 45 + 31 =76 + 16= 9292 + 8 is equal to 100 •
median =3N /4
= 3*100/4 = 75
75 comes under the class of 30-40always see the cumulative frequency .
l= 30
3N/4=75
f=31
Cf = 45
Class interval C= 10
median = 30+ (75-45)/31 *10
= 30+ 0.967*10
= 39.6774.
MODE
classes Frequency
0-10 3
0-10 3 10-20 16
20-30 26
20-30 26 30-40 31
20-30 26 30-40 31 40-50 16
20-30 26 30-40 31 40-50 16 50-60 8
l =30
f0 =26
f1=31
f2= 16
c= 10
mode = 30+((31-26)/2*31-26-16))*10
= 30+( 5/20) *10
=30+0.25*10
32.5