Math, asked by royanubhab89, 6 months ago

Find Median and mode of the following
distribution table
Class Iterval
- 0-10 10-20
20-30
30- 40
40-50 50-60
Frequency
3
16
26
31 16 8 plz explain

Answers

Answered by navyasuresh
2

median = l + ( 3N/4 - CF)/ f * C mode = l + ( f1 - f0 / 2f1 - f0 - f2) * c

MEDIAN

classes Frequency CF

0-10 3 3

10-20 16 19

20-30 26 45

30-40 31 76

40-50 16 92

50-60 8 100

to find cumulative frequency first keep the first value acid is that is 3 next add 16 + 3 then you get 19 + 26 45 45 + 31 =76 + 16= 9292 + 8 is equal to 100 •

median =3N /4

= 3*100/4 = 75

75 comes under the class of 30-40always see the cumulative frequency .

l= 30

3N/4=75

f=31

Cf = 45

Class interval C= 10

median = 30+ (75-45)/31 *10

= 30+ 0.967*10

= 39.6774.

MODE

classes Frequency

0-10 3

0-10 3 10-20 16

20-30 26

20-30 26 30-40 31

20-30 26 30-40 31 40-50 16

20-30 26 30-40 31 40-50 16 50-60 8

l =30

f0 =26

f1=31

f2= 16

c= 10

mode = 30+((31-26)/2*31-26-16))*10

= 30+( 5/20) *10

=30+0.25*10

32.5

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