Question

Find missing number in series 81, 41 , 42, 64.5, ? , 330

Answer 1

Answer:

81× 0.5+0.5=41.

41×1+1=42.

42×1.5+1.5=64.5.

64.5×2+2=131.

Answer 2

The missing number is equal to 131.

Step-by-step explanation:

The given sequence:

81, 41 , 42, 64.5, ? , 330

To find, the value of missing number (?) = ?

The pattern follow:

× 0.5 + 0.5, × 1 + 1, × 1.5 + 1.5, × 2 + 2, × 2.5 + 2.5, .....

41 = $\dfrac{81}{2} +0.5=40.5+0.5=41$

42 = $41\times 1+1=41+1=42$

64.5 = 42 × 1.5 + 1.5 = 63 + 1.5 = 64.5

? = 64.5 × 2 + 2 = 129 + 2 = 131

330 = 131 × 2.5 + 2.5 = 327.5  + 2.5 = 330

∴ Missing number (?) = 131

Thus, the missing number is equal to 131.