find molality of solution obtained when 63 gram of hn O3 is dissolved in 750 gram of H2O
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Moles of HNO₃ = 63 g / (63 g/mol) = 1 mol
Weight of solvent = 750 g = 0.75 kg
Molality = Moles of solute / Weight of Solvent in kg
= 1 mol / (0.75 kg)
= 1.33 molal
Molality of solution is 1.33 molal
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Weight of solvent = 750 g = 0.75 kg
Molality = Moles of solute / Weight of Solvent in kg
= 1 mol / (0.75 kg)
= 1.33 molal
Molality of solution is 1.33 molal
Mark as brainlist
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