Question

Find molarity and molality of a 15 solution of sulphuric acid

Answer 1

Calculate the molarity and molality of a 15% solutions (by weight) of sulphuric acid density 1.020gcm−3.(Atomic masses H=10=16S=32 amu)

1.3048 molar,1.53 molal2.3048 molar,2.53 molal3.3048 molar,3.53 molal4.3048 molar,4.53 molal .

A)  

M=WBMB×VL

Molecular weight of H2SO4=2×1+32+64

⇒98gmol−1

M=15g×100098g/mol×115g×1.02g/cm3

=1500011495.4 molar

=1.3048 molar

m (molality) =WB×1000WB×100g

⇒15g×1098gmol−1

⇒15098

⇒1.53 molal

[COMPLETE THE QUESTION CLEARLY, I HAVE STATED THE QUESTION, IT WAS THE QUESTION NA.]