Question

Find molarity of 1.8g glucose & 6 g urea in 1 litre solution

Answer 1

Number of moles of glucose = 1.8/ molecular mass of glucose=0.01
Therefore molarity of glucose solution= 0.01 M
Number of moles of urea=6/molecular mass of urea=6/60=0.1
Therefore, molarity =0.1/1=0. 1 M
In case your supposed to find the molarity of combined solutions of glucose and urea, just add the number of moles and divide by the given volume, i.e,
0.01 + 0.1/1=0.11 M
I'm not sure whether this is right though