Question

Find molarity of 4.3g H2SO4 is present in 500 cm³ solution?​

Answer 1

Answer:

Explanation:

The molarity is the ratio of the number of miles to the volume of solvent.

According to the question it is given that the mass of solute ( h2so4) is 4.3g and the volume of solution is 500cm^3

So the number of moles of solute = Given Mass / molecular mass

= 4.3/98

Now molarity = (4.3/98)/500cm3

= 4.3/98/5×10^8 = 87.75

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