Question

find moles of electron present in 68 g of NH3​

Answer 1

answer : 40 moles of electron present in 68g of NH3

explanation : given, mass of NH3 = 68g

molar mass of NH3 = 17g/mol

so, number of mole of NH3 = mass of NH3/molar mass of NH3

= 68/17 = 4mol.

we know, number of electrons in one molecule of NH3 = number of electrons in N atom + 3 × number of electrons in H atom

= 7 + 3 × 1 = 10

so, number of moles of electron in 4moles of NH3 = 10 × 4

= 40 mol.

hence, number of moles of electron present in 68g of NH3 = 40 mol

Answer 2

given mass (m) = 68g

atomic mass (M) = 17

n=m/M

68/17

= 4 moles

thanks