Math, asked by abigailbinuabraham, 1 month ago

find n [3/5]^3 x [3/5]^-6 = [3/5] ^2n-1

Answers

Answered by dubeyshoryadubey

0

Answer:

2+87-57+567+6(7+)-57+45688+2822822-266277(-6)÷687×6722722

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