Find n, if first term is 8, nth
term of AP is 62. Sum of first n
terms is 210
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Answer:
a=8,an=62,sn=210
an=a+(n−1)d
62=8+(n−1)d
54=(n−1)d
Sn= 2n[2a+(n−1)d]
210= 2n[16+(n−1)d]
420=n[16+54]
420=70n
n=6
54=(6−1)d
d= 54/5
Step-by-step explanation:
hope it helps you :)
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