find n so that the nth term of the following to A.P.s are the same
1,7,13,19,........... . and 100,95,90,...
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a= first term= 1
d= common difference= 7-1 and 13-7 is 6
n= no. of terms.
thus , nth term = an
an= a+ (n-1)d
an= 1+ (n-1)6
an = 1-6 +6n
an = 6n-5.
and for the second a.p,
a= 100
d= 95-100 and 90-95 = -5
an = a+ (n-1)d
an = 100 + ( n-1)-5
an= 100+5 -5n
an = 105-5n
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