Question

Find n th derivative of sin (3x+5)

Answer 1

Answer:

answer is diwn

Step-by-step explanation:

sin3x=3sinx−4sin3x

⟹y=sin3x=3sinx−sin3x4

y′=14.(3cosx−3cos3x)

⟹y′=14.(3sin(π2−x)−3sin(π2−3x))

y′′=14.(−3cos(π2−x)+32cos(π2−3x))

⟹y′′=14(−3sin(π2−(π2−x))+32sin(π2−(π2−3x)))

⟹y′′=14(−3sin(x)+32sin(3x))

⟹y′′=14(3sin(2∗π2+x)−32sin(2∗π2+3x))