Question

Find net magnetic field at centre of both loops. i.e at point 'O'

see direction of current carefully...


plz don't post irrevelant answer ​

Answer 1

$\bold {\huge {Answer :-}}$

⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯

✭Magnetic Field✭

Let current flowing in loop A be $I_1$

& B = $I_2$

Since we know magnetic field at centre of loop is

$\huge{\boxed{\boxed{B = \frac{\mu_\circ. I}{2R}}}}$

⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯

Therefore, Magnetic field in Loop A is

$\huge{\boxed{\boxed{B_A = \frac{\mu_\circ. I_1}{2R}}}}$

⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯

Magnetic field in loop B is

$\huge{\boxed{\boxed{B_B = \frac{\mu_\circ. I_2}{2R}}}}$

⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯

Here the both loop are perpendicular to each others

Hence the resultant Magnetic field

$B_{net} =\sqrt{B_A^2+B_B^2}\\\Rightarrow\:B_{net} = \sqrt{(\frac{\mu_\circ.}{2R})^2(I_1^2+I_2^2)}\\\Rightarrow\:B_{net}=\frac{\mu_\circ.}{2R}\sqrt{I_1^2+I_2^2}$

Net magnetic field will be x-z plane.

Answer 2

Explanation:

HOPE IT HELPS YOU AND YOU LIKES IT IF YOU LIKE IT PLZZZZZ MARK ME AS BRAINLIST